用STR进行亲权鉴定时结果的判定及其理论根据

发布时间：2018-07-03 18:49

本文选题：亲权鉴定 + 短串联重复　；参考：《中山大学学报(医学科学版)》2004年06期

【摘要】：【目的】探讨亲权鉴定中应该应用的STR基因座的数量及出现矛盾基因座时下结论的标准。【方法】根据基因频率和遗传规律,用计算机模拟1万例亲权鉴定,统计父权指数。根据平均非父排除率和突变率,用二项分布公式计算真父和随机男人出现不同数目矛盾基因座的概率和似然比。【结果】在1万例模拟亲权鉴定中,当检测9个和13个STR基因座时,分别有2%和0.06%的PI小于999。检测17个STR基因座,真父和随机男人出现1个矛盾基因座的似然比为2.3×103。检测24个STR基因座,真父和随机男人出现2个,3个和4个矛盾基因座的似然比分别为1087,1.408和0.002。【结论】亲权鉴定中应该检测13个以上的STR基因座。出现1个和2个矛盾基因座时,应该分别增加检测到17和24个基因座,才能下肯定的结论。检测到3个矛盾基因座时,应该用其它方法作进一步的分析。出现4个矛盾基因座时,可排除父权关系。
[Abstract]:[objective] to explore the number of STR loci to be used in paternity testing and the criteria for drawing conclusions when contradictory loci appear. [methods] according to the gene frequency and genetic law, 10,000 cases of paternity identification were simulated by computer and the paternity index was counted. According to the average non-paternal exclusion rate and mutation rate, the probability and likelihood ratio of different number of contradictory loci in true father and random man were calculated by binomial distribution formula. [results] in 10,000 simulated paternity tests, When 9 STR loci and 13 STR loci were detected, 2% and 0.06% Pi were less than 999, respectively. Among 17 STR loci detected, the likelihood ratio of one contradictory locus between true father and random man was 2.3 脳 103. Among 24 STR loci detected, the likelihood ratios of 2, 3 and 4 contradictory loci in true father and random man were 1087, 1.408 and 0.002, respectively. [conclusion] more than 13 STR loci should be detected in paternity test. When there are 1 and 2 contradictory loci, 17 and 24 loci should be detected, respectively, in order to reach a positive conclusion. When three contradictory loci are detected, further analysis should be made by other methods. When there are 4 contradictory loci, paternity can be excluded.
【作者单位】：中山大学中山医学院法医学系中山大学中山医学院法医学系中山大学中山医学院法医学系中山大学中山医学院法医学系
【基金】：广东省自然科学基金资助项目(79-128) 中山大学“211工程”重点学科资助项目(429008)
【分类号】：D919.4

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